1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 F( v0 D7 r- k6 X# dwww2.tvboxnow.comFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 3 N9 E( v0 g' Q5 R( g0 h3 bFor 123 6 W- ]$ K# y3 Q7 m% g! d. ^公仔箱論壇1x2+1=3 that is 1 time of 3 & R/ c- f4 \: e+ ctvb now,tvbnow,bttvb1x3+1=4 that is 2 times of 2 ( p& Z5 f& W. t9 Z' b- [, xwww2.tvboxnow.com2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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