1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 7 Z$ z' `$ _. N5 Q9 u' p7 R9 V+ zFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 ( D& x& G ^6 k& Dwww2.tvboxnow.comFor 123TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。) q5 P2 {9 {: i7 q) `
1x2+1=3 that is 1 time of 3 . `6 R; z; y" J7 e; L+ J) x% i+ [公仔箱論壇1x3+1=4 that is 2 times of 2www2.tvboxnow.com8 N; G% R- g* x/ F8 X! p
2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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