1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 2 u/ x( K# W MFor 111 would be 1x1+1=2 that is 2 times of 3rd 1 $ l/ F7 E5 O3 Z7 o7 b2 _, m公仔箱論壇For 1239 B1 H o7 ]$ l4 N* b
1x2+1=3 that is 1 time of 3 2 K) m3 s; \; y" G- @1x3+1=4 that is 2 times of 2+ X9 U! q' Q. |/ d
2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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