They would be 111 or 123
& U% S9 x/ D4 I; S0 rFor 111 would be 1x1+1=2 that is 2 times of 3rd 1
8 z, A9 D5 B: Y% y y) O: ~tvb now,tvbnow,bttvbFor 123
; Z* P, Q7 D m! Z, ^7 p _ ltvb now,tvbnow,bttvb1x2+1=3 that is 1 time of 3
* ?& i5 ~. O& A9 i$ l+ e& k1x3+1=4 that is 2 times of 2
3 l {! j1 g0 P2 _1 i8 x: j2x3+1=7 thta is 7 times of 1 |