That is a very simple mathematics question.
5 F& X, w! R" o2 \1 YTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Let x = Male, y = Female, z = Child' a+ z1 | u8 Y
6x + 3y + z/2 = 100 Formula 1
8 L m7 D4 p. @* `) R1 A% Otvb now,tvbnow,bttvbx + y + z = 100 Formula 2tvb now,tvbnow,bttvb3 r% ?4 ?# U: z$ O- G2 m
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
( N% F8 f# Q# }tvb now,tvbnow,bttvbSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
/ a: D( q. E# M1 [公仔箱論壇Formula 4 can change into 11x + 5y = 100 Formula 5
& Y5 q0 J3 b" y LIn Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.公仔箱論壇( ]+ S6 b- M& T1 W
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
7 u" x% K5 c- A+ b/ m5 f3 `& hEventually, the answer is 20 female and 80 children and no male. |