That is a very simple mathematics question.
. Q: `% a2 m, F$ W$ Z- o) eLet x = Male, y = Female, z = Childtvb now,tvbnow,bttvb7 P$ k/ x) e3 e* Y
6x + 3y + z/2 = 100 Formula 1www2.tvboxnow.com6 M' Y9 @6 I7 }
x + y + z = 100 Formula 2
/ N) b! e4 K8 }! Q6 {7 nTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
+ g4 W6 f# {/ ~$ x! |$ C3 ~Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 40 d/ K( B4 D2 X4 ?0 f0 N; s
Formula 4 can change into 11x + 5y = 100 Formula 50 m% v' g1 C9 N2 x! r, }: u3 F$ [) m
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
" j1 t* Q; Y, M+ d8 A( ^. I' AAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
# ]6 m7 u2 b) t6 ?& q V$ Q! M: ]Eventually, the answer is 20 female and 80 children and no male. |