That is a very simple mathematics question.$ [$ I* V1 w4 L) O/ z
Let x = Male, y = Female, z = Child
8 @0 m2 [0 S% P" h V7 r. M公仔箱論壇6x + 3y + z/2 = 100 Formula 15 ~3 C2 t# [0 [% A
x + y + z = 100 Formula 2
. Q4 L1 [ U' i6 p+ Q; m% U( Otvb now,tvbnow,bttvbSimplify Formula 2 into z, we get z = 100 - x - y Formula 3
& p; Q# l; Q# K( f4 t* W- RTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4% i6 n3 s/ H4 x* x0 f9 G
Formula 4 can change into 11x + 5y = 100 Formula 5www2.tvboxnow.com/ E. v \2 P5 Q& C
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
8 Q# H# A6 G8 v h" owww2.tvboxnow.comAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
! d$ \) y! ?0 n8 e: @0 YEventually, the answer is 20 female and 80 children and no male. |