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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
+ K& c: X4 i$ v/ F  m& O8 Ptvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)
. ~# p9 w) _5 b9 t- s$ |8 Y# z& ^/ Cthen 称 them c which side is the heavy 0 V, ]+ F; k% d6 a
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group www2.tvboxnow.com' J- k0 ~4 v) R6 B
if not balance take the heavy and then ( i7 a) W3 N$ P* I3 ?
take the heavy group divided into 2 group i group contain 1 ball than 称 it
5 W* A. A! b+ |% e& {公仔箱論壇than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
+ E" M4 W( A/ v$ R, }6 t; u9 mTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边& L& B: @: X, ~" m
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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