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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
9 ]; A* }+ g; p4 G7 F+ v: ttvb now,tvbnow,bttvb1st u divide the ball into two group (i group 6 ball)8 F  }, S3 S& P6 p/ ~, h, a' K
then 称 them c which side is the heavy
; Q# S" [8 V" F; p1 p2 |( D; Tthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 公仔箱論壇3 K/ U( q) w! c5 o, j5 H
if not balance take the heavy and then
$ a  v, X8 q  |! L% Xtvb now,tvbnow,bttvbtake the heavy group divided into 2 group i group contain 1 ball than 称 it www2.tvboxnow.com  e; d7 s" U1 ~% z
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: www2.tvboxnow.com$ w! F9 R) @3 Z- i4 b
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边0 K3 R, l, B( E/ l( f2 D
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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