返回列表 回復 發帖
see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
. I& d. x$ \/ V. y2 n将比较重的那份再平均分成两份成一次
8 ~5 F  ^& q5 n  w0 s2 W! k公仔箱論壇剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4, t% i# r3 ~: v% h" ^! g
if  (4v4)= same that means the rest of 4 is got more weight公仔箱論壇8 e) }) h) L8 \! a3 ^
    then goto 2 - compare rest of(4)  - 2 with 2 ( f( n+ }  A- J
           if (left side is more weight)www2.tvboxnow.com& U+ z% `$ s  I7 `8 V1 y. p
              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
; l4 }! S, c8 T( O1 y( C, ]2 i公仔箱論壇          else ( right side is more weight)公仔箱論壇2 S1 z( r0 |! W& y8 w( ^
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
' K1 @$ h! m5 R公仔箱論壇else ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
返回列表