put six on each side first
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from the heavier six, split it to three on each side
2 P/ J% X- z) I8 _( Y: R( Ctvb now,tvbnow,bttvb2 Q- ^$ x# k% J E* \/ {
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |