put six on each side first/ j! t m! z9 ?$ Y8 R
0 B. i. T# {# I: P$ \ V- Dfrom the heavier six, split it to three on each side
' M- k% V" K4 }tvb now,tvbnow,bttvbtvb now,tvbnow,bttvb; |# \" }$ G1 O& [2 z
then there is three left, put one on each side, if one is heavier then that is it, if they are balanced then last one is heavy one |