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第2的....直覺告訴我
0000000000
友華
我已經想很久了
- B  U' @9 x' y, |! H. \# n實在太難
* J0 n* S- q3 n, q只好來看答案了
no2,,3,4應該沒那麼容易死瓜

回復第 1 帖由 蘭昀 所發的帖子

number 4 has the best chance to live
5 \7 V' D* H- f- P: `% xassume number 1, 2, 3 and 4, pick number a, b, c and d.
9 j; J/ N4 y( G% w" F+ f公仔箱論壇number 4 knows how many left in the bag which is 100-a-b-cwww2.tvboxnow.com( w& H+ S5 u: \% Z1 s4 z7 _
take the average of (100-a-b-c)
$ B1 T: c) d- `  u2 @then number 4 knows a or b or c must be greater or less than average of (100-a-b-c)
4 ~9 D) S' R: A9 k1 Nand number 4 can squeeze himself into the average and what number 5 picks./ z) l! q) L& e: j  B8 z
so number 4 will have the best chance.
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i hope this is a good logic hehe
同意楼上 Number 4 係最安全!! Number5 係一定死咖了!! 不过我就唔知 Number 1,2,3 边个唔好彩jie !!TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。# g# G; V: D  }7 \; T& U7 l4 J
玩心理咖话!! 5号 好大压力!! 因为就算佢知剩下几多豆 佢豆好难判断所以!!!
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/ h: r- S4 }2 ?) _8 f+ R' m公仔箱論壇如果绝D咖哇!!  全部豆色!!! 1号摞97粒 剩下3粒 一人一粒  大家一锅熟 哈哈!!!!(因为一人要一粒 所以佢哋冇得拣  只可以摞一粒!!)
想不到!!答案呢?
應該是第三ㄍ吧
no 2 !!! no 2 !!!                  
4 M3 b" k( K  ^tvb now,tvbnow,bttvb  t* }7 ]% w2 ^. T; F
             no 1 take 20 ( can be any ) no 2 take 19 ( can be any ) , no 3, 4, 5, take 18, 18, 18. ( `* H8 c1 }# d& l/ N: W
So they will all die !!                                                      3 [# A# L& }2 G7 z8 U

, S9 i! ?" s, Ktvb now,tvbnow,bttvbwww2.tvboxnow.com  c* z6 |( [& O1 k( f

2 n0 C1 i; ]/ QTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。
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Just Joking !!!
The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。6 r# S6 k6 p6 F: N4 j( S, w2 M

1 B: |! |* H- P& A) _8 Fwww2.tvboxnow.comStarting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44.  then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20.  
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. f0 e3 ?6 [' oNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.TVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。4 J# Y+ H' p+ P; |. l+ G) }, U

# q4 }5 l! g' ]/ _+ P( S+ htvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20
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3 h$ z" R; E0 N4 n8 l7 J#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.  j8 _0 y0 F9 t5 [
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#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.
5 ~; r2 @& H/ x! z1 ewww2.tvboxnow.com公仔箱論壇7 j. O- h. x- l5 f/ M
Ended all have the same number and all died.
我猜NO4,
% t5 C$ H( ^, }9 B& s因為他可以取前面三位豆子的平均數,tvb now,tvbnow,bttvb7 D( [5 a) T# [
也可以防止豆子不夠讓NO5墊底。
最后一个人最安全!因为当四个人拿完之后,他可以拿quarter of 之前拿的总数,咁样嘅话,佢係最大或者最小的几率係最低嘅```而前面几个人,用呢种方法摞会係最大或者最小的几率会比5号大D...而呢种方法係最有效避免最大或者最小嘅
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[ 本帖最後由 289675283 於 2006-12-15 01:21 AM 編輯 ]
[-X  所謂IQ題唔喺可以用普通思維gē,
* D( B$ }, ^% _, k4 j) Swww2.tvboxnow.comTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。$ \0 _! g9 K" Z; b4 b5 n: @0 v
答案應該喺 :抓豆子不多不少的那個囚犯存活率是最大的
想想
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