標題: [IQ題] 2 Math related IQ problems [打印本頁] 作者: orotot 時間: 2012-4-6 04:00 AM 標題: 2 Math related IQ problems
I just read these last week. I hope these are new in here. * J1 m, V5 t, l0 T& J8 Qwww2.tvboxnow.com 7 @: f: p5 \7 F" `. ~/ n9 K#1) What is the next sequence?+ x; ~% f# h- \: B3 ?5 x$ G
公仔箱論壇6 P3 d) K/ S0 T( J6 x( P
1, 11, 21, 1211, 111221, ????www2.tvboxnow.com3 Y) }& I. J. P2 W, G
The numbers in this series describe how the previous number is formed. 5 X: v$ r( _+ f% G2 X. l8 V% V: E+ R. u. J: p, t3 j V
The first no. is 1公仔箱論壇4 Q6 q! z$ x' ?
The next one describe it: there is only one "1", therefore 11公仔箱論壇% g1 V* t/ h4 d4 K# c: A* [
The next one describe the "11" as there are two "1", therefore 21 # F5 }- Q( r' q2 J$ F1 f) GThe next one describe the "21" as there are one "2" and one "1", therefore 1211公仔箱論壇" M5 _# f2 j6 Y. m
The next one describe the "1211" as there are one "1", one "2" and two "1", so 1112213 z* L) Q* K+ V% h. C
The next one describe this "111221" is three "1", two "2" and one "1" so the answer is: 7 n; |0 r' p w3 [7 t1 C$ I z/ P3122114 i9 I& f$ }& W* n- y$ g
2 l$ v2 [, A6 } fI give up on question two.作者: irismylam 時間: 2012-6-23 08:40 AM
question 2 answer unavailable作者: gm3stevens 時間: 2012-6-23 11:35 AM
本帖最後由 gm3stevens 於 2012-6-23 06:56 PM 編輯 $ i1 D# c( S; U2 d% X$ X
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After seeing the IQ question 據說這是蘋果公司的面試題, it reminds me of grouping the left hand side numbers to reflect the number on the right. + `: E% q6 @" Z% z公仔箱論壇* I1 r! h- U1 t! e
So the right hand side number 0 can be represented by number 1 4 ~6 z/ i, I! N p( V7 G4 l7 ?TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。The right hand side number 1 can be represented by 3,1,2,9,7,5www2.tvboxnow.com* {. Y7 r3 I( M# q
The right hand side number 2 can be represented by 2,5,8,1,6,7,3,02 i' R% l) D b' }6 E
The right hand side number 3 can be represented by 5,9,8,3tvb now,tvbnow,bttvb) l% H" k9 C6 Q3 w0 P. |( J. ~# |
The right hand side number 4 can be represented by 6 ; u7 E4 T, K2 V公仔箱論壇Now the question is 8136, check the above list, 8,1,3,6 are grouped under 2. Therefore, the answer is 2 # q7 l& T, y6 Q2 K- V3 W ! T9 m4 w M) Mtvb now,tvbnow,bttvbSorry. My bad. Someone told me that it is actually counting the number of holes in the given number. 7 Z( J- _' y$ H" P" l* VThere are 3 holes in 8136, two from number 8 and one from number 6 so the answer is 3. + V3 e+ n5 k8 \ / E9 `0 a; [2 W! Z- e/ ftvb now,tvbnow,bttvb, a) e6 i) {- r0 @# H. d3 v
