gm3stevens

The numbers in this series describe how the previous number is formed.tvb now,tvbnow,bttvb; ]& L, E' K% B
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The first no. is 11 ^/ O8 q( }) d) w- W
The  next one describe it: there is only one "1", therefore 11: d' x* F& T7 t2 Y9 J& W5 @
The next one describe the "11" as there are two "1", therefore 21
& \) D) r2 _1 ?( q2 c8 [+ dThe next one describe the "21" as there are one "2" and one "1", therefore 1211www2.tvboxnow.com9 b# \# E* x0 T
The next one describe the "1211" as there are one "1", one "2" and two "1", so 111221TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。' v  J/ y. ^5 X* W3 `
The next one describe this "111221" is three "1", two "2" and one "1" so the answer is:
2 d, F4 U, ]* q" O公仔箱論壇312211& @2 f! ]* a: i* p* _2 f' |

% H" D" V6 y: H- Q8 V/ YI give up on question two.

gm3stevens

6 d" o, L' S6 p7 ^TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。
5 U8 L7 l' Z* K8 {2 H4 ]% {After seeing the IQ question 據說這是蘋果公司的面試題, it reminds me of grouping the left hand side numbers to reflect the number on the right.www2.tvboxnow.com; S1 u* B" [. e/ @5 w! B) {
TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。0 P& Y+ o0 S6 e5 T$ E! R
So the right hand side number 0 can be represented by number 1
2 \; \$ ]3 k9 Gtvb now,tvbnow,bttvbThe right hand side number 1 can be represented by 3,1,2,9,7,5tvb now,tvbnow,bttvb: u, A3 ?. e6 b9 E1 f- @6 R
The right hand side number 2 can be represented by 2,5,8,1,6,7,3,0
1 L, r5 k0 k& o1 F0 |5 @( F1 J* F% utvb now,tvbnow,bttvbThe right hand side number 3 can be represented by 5,9,8,3
, v  g  l6 f/ |' E( }www2.tvboxnow.comThe right hand side number 4 can be represented by 6
* Y+ R$ Z, G, g% v8 }, T5 N! {& Atvb now,tvbnow,bttvbNow the question is 8136, check the above list, 8,1,3,6 are grouped under 2. Therefore, the answer is 2. i! Q5 z( I9 P& s

  C: Q) H5 F. b1 S" wwww2.tvboxnow.comSorry. My bad. Someone told me that it is actually counting the number of holes in the given number. $ o* `8 M) ^) d( j3 @5 F  N
There are 3 holes in 8136, two from number 8 and one from number 6 so the answer is 3.( }% E  a5 @1 z) L2 e% L

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