twinsdragon

That is a very simple mathematics question.
+ V" q! e( e! L8 S( o4 uwww2.tvboxnow.comLet x = Male, y = Female, z = Child
( C* H" f, _3 p9 A6x + 3y + z/2 = 100   Formula 1
' u9 w" `- Y* lTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。x + y + z = 100    Formula 2' p2 d# T! q+ E) V' @0 I
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
& Y( d/ h! b& _/ V& h& _8 ZSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4  u; s3 R# b+ K3 H& S6 k" o# A
Formula 4 can change into 11x + 5y = 100 Formula 5tvb now,tvbnow,bttvb  L. }* d- r/ Y  O
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
( g" j+ E& M; G" c( @tvb now,tvbnow,bttvbAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.
9 n7 o: |. H  A$ w" e. mwww2.tvboxnow.comEventually, the answer is 20 female and 80 children and no male.