twinsdragon

That is a very simple mathematics question.' C  M% {1 M% x! l" h+ S$ T/ `
Let x = Male, y = Female, z = Child
) U* _3 p3 }1 w3 `: Q2 }公仔箱論壇6x + 3y + z/2 = 100   Formula 1
$ d/ t! y  `* {' X. m! A* J公仔箱論壇x + y + z = 100    Formula 2# G+ Z2 X& k# M8 o: |
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3) \5 |5 a4 s# V" I
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
! t, I5 X3 ]5 iFormula 4 can change into 11x + 5y = 100 Formula 5
7 H8 J0 o+ ~" G2 _TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。1 G: t; Q/ r8 b7 }8 g( z+ N
And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.tvb now,tvbnow,bttvb5 C7 Q! K9 t$ F% h* M1 y: e! f
Eventually, the answer is 20 female and 80 children and no male.