That is a very simple mathematics question.
' ]$ E1 P9 e% V6 WLet x = Male, y = Female, z = Childtvb now,tvbnow,bttvb9 F2 V# `1 X8 M r: U
6x + 3y + z/2 = 100 Formula 1
5 x& H" N/ N. K: m( \ T: O7 P, `www2.tvboxnow.comx + y + z = 100 Formula 2www2.tvboxnow.com0 k' t+ }5 _. J, \
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3
2 R( |8 S; P- @% o, s' r: h! r3 oSub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
, E, A0 C2 v5 @Formula 4 can change into 11x + 5y = 100 Formula 5
" q7 ~( A2 H0 u( lTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
7 P7 X! {& [* e5 P: ETVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。And between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.公仔箱論壇* D* b; u( i1 l! a, Z$ g% o
Eventually, the answer is 20 female and 80 children and no male. |