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發表於 2010-9-17 09:31 PM | 只看該作者 ::: 一按馬上把這個話題放上你的facebook!! :::

[IQ題] [數學題] 為什麼一個整數(大於六)在兩個質數之間，可總是分為六?

為什麼一個整數(大於六)在兩個質數之間，可總是分為六? (5,6,7; 11,12,13; 17,18,19; 29,30,31 etc)
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9 e) z" V! X1 u# Y5 jwww2.tvboxnow.comWhy an integer, that is greater than six and is between two prime numbers, can be always divided by six? (5,6,7; 11,12,13; 17,18,19; 29,30,31; etc)公仔箱論壇+ H( e1 G: @9 s7 N

1 a; |0 i. b$ `# H' i! ?# BAnswer will be provided on Sunday (19 Sept 2010)..
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idontlikeapple

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發表於 2010-9-18 08:26 PM | 只看該作者 ::: 一按馬上把這個話題放上你的facebook!! :::
這是因為質數始終是奇數，所以下一個數字始終是一個偶數是可分兩。此外，每三個數字序列中，必須有一個整數是可分三。如果一個序列的三個整數包含兩個素數和一個整數，該整數必須可分三。該整數既是可分兩和三，因此，可分六。
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It is because that prime number is always an odd number, so the next number is always a even number that is dividable by two. In addition, every three number in a sequence, there must be an integer that is dividable by three. If a sequence of three integers contains two prime numbers and an integer, and that integer must be dividable by three. That integer is both dividable by two and three, thus, dividable by six.
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