1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 4 p9 e1 w8 ]; h5 M# k* a公仔箱論壇For 111 would be 1x1+1=2 that is 2 times of 3rd 1 5 C, P8 O+ H# m+ |公仔箱論壇For 123 # L2 }) P7 F# m! f公仔箱論壇1x2+1=3 that is 1 time of 3 1 Z' |% K7 B6 g4 `1x3+1=4 that is 2 times of 2 1 C3 {" F# d$ ~8 b- r6 |7 Zwww2.tvboxnow.com2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
| 
