1 1 1, because any number can have factor of 1. also, only 1 can be true if any random number multiple plus has to be divided by the remaining digit. So, 1 1 1 is my answer.
They would be 111 or 123 3 n3 r4 F4 {$ n' I. ]For 111 would be 1x1+1=2 that is 2 times of 3rd 1 # m0 {* d/ j2 ]! c. Bwww2.tvboxnow.comFor 123& E% p1 D- d* o5 `
1x2+1=3 that is 1 time of 3www2.tvboxnow.com5 K8 D! I9 H1 K
1x3+1=4 that is 2 times of 21 ^) |% k4 ~( s" R; n7 ~
2x3+1=7 thta is 7 times of 1
發表於 2009-8-19 02:33 PM
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