That is a very simple mathematics question.# t- N2 Q, X" Q0 S3 p+ e
Let x = Male, y = Female, z = Child
K5 h; U; k' j; \ o+ l6x + 3y + z/2 = 100 Formula 1
% ~$ _0 j% z5 I8 | Xx + y + z = 100 Formula 2tvb now,tvbnow,bttvb: w) M) @6 M/ T% G
Simplify Formula 2 into z, we get z = 100 - x - y Formula 3www2.tvboxnow.com" r; d% ~- O# a0 U5 K
Sub Formula 3 into Formula 1, we get 6x + 3y + ( 100 - x - y )/2 = 100 Formula 4
, Z, t9 O( x; J+ Ytvb now,tvbnow,bttvbFormula 4 can change into 11x + 5y = 100 Formula 59 ]+ {# d; W2 D
In Formula 5, x can only be 0 - 9, otherwise y will be negative number which we dont want.
5 i: U- \7 M% d1 `8 H$ S% Lwww2.tvboxnow.comAnd between 0 and 9, only 0 can give me a single number of y. So, x has to be 0 and y have to be 20. Then put x and y back to formula 1, we get z = 80.www2.tvboxnow.com3 \% x% c, m% f$ }4 o; v
Eventually, the answer is 20 female and 80 children and no male. |