this is too easy!!9 M$ K7 D2 [8 D9 g3 D! I7 M
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1. put 6 at each side.. take the one side which is heavier; F: I& x7 p: ^0 N. W
2. put 3 at each side.. also take the heavier side
$ K! } g/ j( O8 ~9 @3 o4 ^3. put 1 at each side.. if the weight balance then the one not put inside is the heavy ball.. else the side which is heavier is the heavier ball.. |
發表於 2009-1-7 05:31 AM
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