1 - compare 4 with 4
$ B+ S' K0 F. q0 _公仔箱論壇if (4v4)= same that means the rest of 4 is got more weight公仔箱論壇; I( ^( Z+ f( a& X, |/ J$ Z) L
then goto 2 - compare rest of(4) - 2 with 2
0 w) T0 c' G$ T) H8 \6 y4 b/ a if (left side is more weight)
' T/ c) l7 T6 j+ dtvb now,tvbnow,bttvb then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
7 C; E- u7 C- o4 _www2.tvboxnow.com else ( right side is more weight)
; a5 f. f0 {1 C+ n# sTVBNOW 含有熱門話題,最新最快電視,軟體,遊戲,電影,動漫及日常生活及興趣交流等資訊。 then goto 3 - compare last (right side of (2) - 1 with 1 => get answerwww2.tvboxnow.com+ p" C6 _5 |$ |
else ( the left 4) then compare with above , or right 4 also can compare above method... |