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see xia da an
want to know
我来看看
check ans..
6 and 6 then 3 and 3 then 1 and 1
5識答?
thank you
将12个乒乓球分成平均两份,称一次
( y' W% F9 R# @9 U将比较重的那份再平均分成两份成一次
: ~- {. |! l& Z6 N# x; Qtvb now,tvbnow,bttvb剩下3个随意拿两个来称,如果天平平衡就是第三个,如果不平衡就是重的那个
thank
Thanks!
第一次系一边四个,一边四个秤既
1 - compare 4 with 4www2.tvboxnow.com1 g' j9 H6 X4 Z2 `4 {
if  (4v4)= same that means the rest of 4 is got more weight
' P2 o2 [" v0 M6 W+ R    then goto 2 - compare rest of(4)  - 2 with 2
( l6 P: _  I: p5 Etvb now,tvbnow,bttvb           if (left side is more weight)
8 J* S5 i( a4 _/ H( S公仔箱論壇              then goto 3 - compare last (left side of ( 2) - 1 with 1 => get answer
& W, a, ~% o% A  O' V, n公仔箱論壇          else ( right side is more weight)tvb now,tvbnow,bttvb! g  C$ U3 j7 f; V. A
              then goto 3 - compare last (right side of (2) - 1 with 1 => get answer
( T0 d9 x4 U4 y9 z+ P& N" n: Aelse ( the left 4) then compare with above  , or right 4 also can compare above method...
想了好久都不行
我的做法与4楼的做法一致,这样应该可以排除出来。但这个题目有个漏洞,只说重量异常,没说是重了,还是轻了。
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