The best chance is #3 because all he needs is take #1 + #2 divide by 2. e.g. #1+#2=28 then he take 14. This is the best chance to avoid being highest or lowest and worst case scenario is he equals #1 & #2. However because all 5 knows this simple theory so I think they all died because they all ended up picking the same number of beans.
7 }- {- s, `8 Y- ?! H, n# o) fTVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。+ t# [! w: Z2 C5 d" e e5 g% ^& E Y
Starting from #1, he knows he cannot pick anything bigger then 49 because if he did, then #2 only have to leave 3 beans for #3 #4 & #5 then he'll live. e.g. #1 picked 53 then #2 picks 100-53-3=44. then A,C,D,E all died. e.g. #1=53, #2=(100-53-3)=44, #3=1, #4=1, #5=1. The best chance for #1 is to pick anything less then or equal the median 20 (100 divided by 5). In fact anything between 3-20 won't change the result. Let's say #1 pick 20. TVBNOW 含有熱門話題，最新最快電視，軟體，遊戲，電影，動漫及日常生活及興趣交流等資訊。 I' n! _; D6 M% f0 n
/ n: d8 _: b. uNow #2 knows whatever he picks, #3 will take the median between him & #1 e.g. now #1 picked 20, if he pick 6 then #3 will pick 13 putting him either being the lowest or highest. He cannot allow that so the best chance is to match #1, so he picked 20 as well.. H- e: l5 T8 ?& e0 E
* _4 ~8 k; H% Y7 T; etvb now,tvbnow,bttvb#3 did the obvious choice 40 divided by 2 =20, so he picked 20www2.tvboxnow.com# X1 d" b. r0 b+ |# L
1 }6 X3 i. n2 i% S* J#4 base on knowing the median rule take 60 divided by 3 =20, so he picked 20 as well.
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" p2 R8 K8 k' N8 l& u#5 same as above, he takes 80 divided by 4 =20, picked 20 as well.公仔箱論壇$ |5 O- R( C. A) J% j" S2 a! P
3 G0 g2 I: U) H) k! D$ Y0 ]/ i7 O+ vtvb now,tvbnow,bttvbEnded all have the same number and all died. |
發表於 2006-12-9 12:41 AM
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