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答案!!!!!!!!!答案!!!!!!!!!!!答案!!!!!!!!!!!!!1
^:)^ >:D<
thx
let cc
not possible
不知道要怎麼做阿??
hao

the model answer is stupid

there got more simple way to do it, just read my way, the one i answered before
the
see 了
第一次,一边5个称,若质量没有异常就只称剩下的2个就知道异常的那个了;若有异常就把异常的那5个用一边2个称第二次,若没有异常就是剩下的那个异常了,若有异常就把异常的那2个再2一边1个称第三次就知道了
how?
先分3个一堆
! R; ?; @, y& f! O  ntvb now,tvbnow,bttvb共四堆
  z) {7 L3 b: t, J( q* O4 F* mtvb now,tvbnow,bttvb称两次得出异常的在那一堆,其轻重
; M- h& N7 Y2 W* @2 `tvb now,tvbnow,bttvb在异常的那一堆中在称一次tvb now,tvbnow,bttvb7 B2 i3 r  W# m8 X$ ]: I' u
就可以找到了
divde the 12 balls into 3 sets of 4. # m0 s6 F4 W% S& N+ W
weight any 2 sets.
4 W! j, |6 Y  e; i; Mwww2.tvboxnow.comif the 2 sets are equal, then you know the heavy one is in the third
; c9 ?: X( Q9 H1 B( y1 B" @/ Vif one of the 2 is heavier, then the heavy one is in that set
! \9 F" `. z1 }5 M& V7 l: ~tvb now,tvbnow,bttvbthen divide the 4 balls into 2.1 v# B* Q% M( \
weigh themtvb now,tvbnow,bttvb9 j9 V6 J3 [# b  z5 L3 {
and divide the heavier into 1
2 X9 w% G/ Y% V, J2 T% {3 R6 yand weight them.4 T2 X" A; g& j
3 x weighing and get the ans.  公仔箱論壇; U* p# T- P3 P8 V  {# q  {5 ]4 u3 h
in less than 15 secs.
1. 6 aside and weight.
4 S0 u% o. P1 }www2.tvboxnow.com2. heavier side from (1), 3 aside weight again.www2.tvboxnow.com' m: G5 ~( v1 R  V$ N
3. heavier side from (2), take 2 out of 3 to weight. If equal weight the one not on the scale is the heavier one. else the heavier one on the scale is the odd one. www2.tvboxnow.com/ |4 V. a: }9 H" `0 s# ]7 ?4 A

6 z! L, v6 P, j3 [but i have a question. 重量異常 can be heavier or lighter.... so......
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