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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^www2.tvboxnow.com2 k) q9 F% D: G7 h+ Z8 F0 }6 [
1st u divide the ball into two group (i group 6 ball)tvb now,tvbnow,bttvb3 r% S6 ~  a" a7 w# c8 A5 }8 _+ A
then 称 them c which side is the heavy
; {" V' s" {/ [+ W. d, Hthen use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group 1 e$ I+ k: J8 P1 {7 E4 K: m$ @
if not balance take the heavy and then
+ y2 u* t. {- Z7 }www2.tvboxnow.comtake the heavy group divided into 2 group i group contain 1 ball than 称 it   a  d7 s( E9 M: {# D: h: ?1 T
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14:
1 w6 X/ U! A, ]$ s- d% W(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边, \5 L; ~3 z9 @( t; l$ N" E4 W' i
然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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