divide 12 into 6 one side n balance it..tvb now,tvbnow,bttvb. U6 z, G; j3 Y. p' P
den take da heavier side which is 6 n divide into 2 parts again..
4 T3 s# `& g. ?. x; x% [6 E$ G3 one side n another 3 another side..1 G9 |: q+ m3 h( d1 h
den u take da heavier part again..公仔箱論壇* ?$ H$ x z/ z/ o7 y6 q
now u left 3 pingpong.. u can simply choose 2 of it n balance again..6 c3 u& f. r9 s0 |- s
if one of it is da heavy wan.. da balance will drop one side.. if both are da same.. den da balance hav no changes n da leftover one is da heavy wan |