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回復 #1 MagicAndy 的帖子

i wan to know
thx.~
thank you for sharing
look at it
i noe de ans cauz 1 do b4 already ^^
9 l; e- a2 Q/ O7 ]$ g% Z4 q1st u divide the ball into two group (i group 6 ball)
* j& C  {/ k5 gtvb now,tvbnow,bttvbthen 称 them c which side is the heavy www2.tvboxnow.com9 _1 G2 z8 l8 \( b5 T! s8 i% X' ~  t
then use the heavy side divide into 3 group 1group contain 2 ball 称 the 1st n 2nd group if its balance use the 3th group tvb now,tvbnow,bttvb" j0 Z* R7 }, j& L
if not balance take the heavy and then 公仔箱論壇. N  ~- K) L& a
take the heavy group divided into 2 group i group contain 1 ball than 称 it 公仔箱論壇6 ]5 M( x/ j$ a$ S3 C
than the heavy ball is the ball u wan

回復 #1 MagicAndy 的帖子

how??????????
Oh..i did the same way as the first answer~am i wrong??Let me check~:onion18:
分三次算的话,每次分四粒来算,意思说当有一边较重时,只需要随意将其中六粒拿出来就知道那一粒是异常的了:onion14: tvb now,tvbnow,bttvb8 f  p2 `& {2 x
(不知各位知不知道小弟说的解答,因为小弟不擅长解说)
thx 4 sharing
顶......

回復 #1 MagicAndy 的帖子

顶.......
简单到。。分3份。。每份4个。。第一次称。。必然知道3份中哪份包括异常的。。第二次..把包括的那份2:2的称。。又知道异常的一边
+ ~7 A) K6 t3 ^- E! @( vtvb now,tvbnow,bttvb然后。。1:1。。就知道了··
看解答!!!!!!!!!!!!!!
cccccc
idk..show me
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